Optimal. Leaf size=42 \[ \frac{\left (a+b x^2\right )^6 (A b-a B)}{12 b^2}+\frac{B \left (a+b x^2\right )^7}{14 b^2} \]
[Out]
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Rubi [A] time = 0.18201, antiderivative size = 42, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.111 \[ \frac{\left (a+b x^2\right )^6 (A b-a B)}{12 b^2}+\frac{B \left (a+b x^2\right )^7}{14 b^2} \]
Antiderivative was successfully verified.
[In] Int[x*(a + b*x^2)^5*(A + B*x^2),x]
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Rubi in Sympy [A] time = 20.4966, size = 34, normalized size = 0.81 \[ \frac{B \left (a + b x^{2}\right )^{7}}{14 b^{2}} + \frac{\left (a + b x^{2}\right )^{6} \left (A b - B a\right )}{12 b^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x*(b*x**2+a)**5*(B*x**2+A),x)
[Out]
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Mathematica [B] time = 0.0415072, size = 107, normalized size = 2.55 \[ \frac{1}{84} x^2 \left (42 a^5 A+21 a^4 x^2 (a B+5 A b)+70 a^3 b x^4 (a B+2 A b)+105 a^2 b^2 x^6 (a B+A b)+7 b^4 x^{10} (5 a B+A b)+42 a b^3 x^8 (2 a B+A b)+6 b^5 B x^{12}\right ) \]
Antiderivative was successfully verified.
[In] Integrate[x*(a + b*x^2)^5*(A + B*x^2),x]
[Out]
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Maple [B] time = 0.002, size = 124, normalized size = 3. \[{\frac{{b}^{5}B{x}^{14}}{14}}+{\frac{ \left ({b}^{5}A+5\,a{b}^{4}B \right ){x}^{12}}{12}}+{\frac{ \left ( 5\,a{b}^{4}A+10\,{a}^{2}{b}^{3}B \right ){x}^{10}}{10}}+{\frac{ \left ( 10\,{a}^{2}{b}^{3}A+10\,{a}^{3}{b}^{2}B \right ){x}^{8}}{8}}+{\frac{ \left ( 10\,{a}^{3}{b}^{2}A+5\,{a}^{4}bB \right ){x}^{6}}{6}}+{\frac{ \left ( 5\,{a}^{4}bA+{a}^{5}B \right ){x}^{4}}{4}}+{\frac{{a}^{5}A{x}^{2}}{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x*(b*x^2+a)^5*(B*x^2+A),x)
[Out]
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Maxima [A] time = 1.3572, size = 161, normalized size = 3.83 \[ \frac{1}{14} \, B b^{5} x^{14} + \frac{1}{12} \,{\left (5 \, B a b^{4} + A b^{5}\right )} x^{12} + \frac{1}{2} \,{\left (2 \, B a^{2} b^{3} + A a b^{4}\right )} x^{10} + \frac{5}{4} \,{\left (B a^{3} b^{2} + A a^{2} b^{3}\right )} x^{8} + \frac{1}{2} \, A a^{5} x^{2} + \frac{5}{6} \,{\left (B a^{4} b + 2 \, A a^{3} b^{2}\right )} x^{6} + \frac{1}{4} \,{\left (B a^{5} + 5 \, A a^{4} b\right )} x^{4} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^2 + A)*(b*x^2 + a)^5*x,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.206943, size = 1, normalized size = 0.02 \[ \frac{1}{14} x^{14} b^{5} B + \frac{5}{12} x^{12} b^{4} a B + \frac{1}{12} x^{12} b^{5} A + x^{10} b^{3} a^{2} B + \frac{1}{2} x^{10} b^{4} a A + \frac{5}{4} x^{8} b^{2} a^{3} B + \frac{5}{4} x^{8} b^{3} a^{2} A + \frac{5}{6} x^{6} b a^{4} B + \frac{5}{3} x^{6} b^{2} a^{3} A + \frac{1}{4} x^{4} a^{5} B + \frac{5}{4} x^{4} b a^{4} A + \frac{1}{2} x^{2} a^{5} A \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^2 + A)*(b*x^2 + a)^5*x,x, algorithm="fricas")
[Out]
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Sympy [A] time = 0.168778, size = 133, normalized size = 3.17 \[ \frac{A a^{5} x^{2}}{2} + \frac{B b^{5} x^{14}}{14} + x^{12} \left (\frac{A b^{5}}{12} + \frac{5 B a b^{4}}{12}\right ) + x^{10} \left (\frac{A a b^{4}}{2} + B a^{2} b^{3}\right ) + x^{8} \left (\frac{5 A a^{2} b^{3}}{4} + \frac{5 B a^{3} b^{2}}{4}\right ) + x^{6} \left (\frac{5 A a^{3} b^{2}}{3} + \frac{5 B a^{4} b}{6}\right ) + x^{4} \left (\frac{5 A a^{4} b}{4} + \frac{B a^{5}}{4}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x*(b*x**2+a)**5*(B*x**2+A),x)
[Out]
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GIAC/XCAS [A] time = 0.226793, size = 167, normalized size = 3.98 \[ \frac{1}{14} \, B b^{5} x^{14} + \frac{5}{12} \, B a b^{4} x^{12} + \frac{1}{12} \, A b^{5} x^{12} + B a^{2} b^{3} x^{10} + \frac{1}{2} \, A a b^{4} x^{10} + \frac{5}{4} \, B a^{3} b^{2} x^{8} + \frac{5}{4} \, A a^{2} b^{3} x^{8} + \frac{5}{6} \, B a^{4} b x^{6} + \frac{5}{3} \, A a^{3} b^{2} x^{6} + \frac{1}{4} \, B a^{5} x^{4} + \frac{5}{4} \, A a^{4} b x^{4} + \frac{1}{2} \, A a^{5} x^{2} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^2 + A)*(b*x^2 + a)^5*x,x, algorithm="giac")
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